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Q: What is the sin of 270 degrees?

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270 degrees is West.

Since a full turn is 360 degrees, 270 degrees is 270/360 of a full turn.

(-270) degrees Celsius = (-454) degrees Fahrenheit

sin(0) = 0, sin(90) = 1, sin(180) = 0, sin (270) = -1 cos(0) = 1, cos(90) = 0, cos(180) = -1, cos (270) = 0 tan(0) = 0, tan (180) = 0. cosec(90) = 1, cosec(270) = -1 sec(0) = 1, sec(180) = -1 cot(90)= 0, cot(270) = 0 The rest of them: tan(90), tan (270) cosec(0), cosec(180) sec(90), sec(270) cot(0), cot(180) are not defined since they entail division by zero.

An angle of 270 degrees is 3/4 of a turn.

sin 57 degrees

For angles greater than 360 degrees, subtract multiples of 360 so that the relevant angle (the remainder) is between 0 and 360 degrees. Then For 90 < x â‰¤ 180 deg, sin(x) = sin(180-x) For 180 < x â‰¤ 270 deg, sin(x) = -sin(x-180) For 270 < x â‰¤ 360 deg, sin(x) = -sin(360-x)

360 degrees are supposed to be in a quadrilateral so 360 - 270 = 90 degrees

270 degrees

3 because 3*90 = 270 degrees

270 degrees

270 degrees is a reflex angle and is 3/4 0f a turn

There are no degrees of sin, all sin is sin

-270 degrees = -4.7 radians.

There are 270 degrees in 3/4 of a rotation

90+90+90=270 degrees your answer is 270 degrees

It is: 9/5*(-270)+32 = -454 degrees Fahrenheit

There is no such thing as "north of 270 degrees". Latitudes (north or south) go from 0 to 90 degrees.

Yes, by 30 degrees.

270 degrees

270 degrees

There are 270 degrees

270 degrees

90 degrees 180 degrees 270 degrees 360 degrees!

cosecant(x) = 1/sin(x) = -1sin(x) = -1x = 270 degrees(plus or minus any whole multiple of 360 degrees)